C++中 i=i; 与 *p=i; 对应的汇编代码为什么不一样? - V2EX
huzhikuizainali

C++中 i=i; 与 *p=i; 对应的汇编代码为什么不一样?

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  •   huzhikuizainali Feb 23, 2024 1114 views
    This topic created in 810 days ago, the information mentioned may be changed or developed.
    《 C++ Primer 》 P48 问这个问题的目的是希望更深入理解 C++的指针
    int i=42;
    int &r=i;
    int *p=&i;
    *p=i;
    i=i;

    上述 C++代码中 i=i; 与 *p=i; 对应的汇编代码为什么不一样?
    godbolt.org
    *p=i; 对应如下汇编语言
    mov edx, DWORD PTR [rbp-20]
    mov rax, QWORD PTR [rbp-16]
    mov DWORD PTR [rax], edx

    i=i;对应如下汇编语言
    mov eax, DWORD PTR [rbp-20]
    mov DWORD PTR [rbp-20], eax
    shendaowu
        1
    shendaowu  
       Feb 23, 2024
    我猜 OP 是不是因为这两个在这个上下文环境中是等价的,所以认为汇编代码也应该是一样的?我猜在开启编译优化之后编译器可能会发现嗦的地方并优化掉。但是一般情况下应该是将代码逐字逐句地翻译成汇编语言的,比如 DEBUG 版。
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