如何用python实现百度地图墨卡托坐标跟经纬度坐标互转? - V2EX
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pc10201

如何用python实现百度地图墨卡托坐标跟经纬度坐标互转?

  •  
  •   pc10201 Jan 1, 2014 12431 views
    This topic created in 4507 days ago, the information mentioned may be changed or developed.
    从百度地图的js中获取到了一部分数据

    "name":"多味小吃店(荣华东道)","overall_rating":"3.5","pc_bookable":0,"phone":"(021)62088786","poi_address":"上海长宁区荣华东道19弄1楼3号C室(近水城南路)","point":{"x":13514570.1,"y":3636377.2},"price":"40","service_rating":"3","shop_hours_flag":1,"tag":"美食,韩国料理,古北","wap_bookable":0},"src_name":"cater}

    里面的point":{"x":13514570.1,"y":3636377.2}数据转换成坐标即是
    121.39532, 31.19393

    如何用python实现百度地图墨卡托坐标跟经纬度坐标互转?
    最好是不用百度的API,直接计算
    8 replies    1970-01-01 08:00:00 +08:00
    zavior
        1
    zavior  
       Jan 1, 2014
    其实。。这样转换违反国家相关法律
    est
        2
    est  
       Jan 1, 2014
    lazycat
        3
    lazycat  
       Jan 2, 2014 via Android
    @zavior 为什么。。。
    dancingbear
        4
    dancingbear  
       Jan 2, 2014
    没有这样的逆向算法吧
    zavior
        5
    zavior  
       Jan 2, 2014
    @lazycat 因为奇葩天朝法律规定,地图的坐标必须有偏移,任何从火星坐标转换回地球坐标的行为都是违法的。
    phyng
        6
    phyng  
       Jan 2, 2014
    import math

    mercator = {"x":13514570.1, "y":3636377.2}
    lOnlat= {}

    x = mercator['x']/ 20037508.3427892 * 180
    y = mercator['y']/ 20037508.3427892 * 180

    lonlat['x'] = x
    lonlat['y'] = 180 / math.pi * (2 * math.atan(math.exp(y * math.pi / 180)) - math.pi / 2)

    print lonlat

    这样得到的结果是{'y': 31.027932178384102, 'x': 121.40344879134716}
    有误差可能出在20037508.3427892以及math.pi

    偏移问题不是指这个,偏移是实际坐标要经过我朝保密插件处理成假坐标,而墨卡托坐标跟经纬度坐标互转是有公开算法的对地球的不同表示。参考http://www.cnblogs.com/liongg/archive/2009/04/20/1439905.html
    http://bbs.esrichina-bj.cn/esri/viewthread.php?tid=78245
    pc10201
        7/span>
    pc10201  
    OP
       Jan 3, 2014
    @phyng "point":{"x":13514570.1,"y":3636377.2}请问这个坐标到底是国际的墨卡托坐标还是我朝加密后的火星坐标?
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