请教一个比较麻烦的 Oracle 转 Mysql 的问题 - V2EX
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darnurash
V2EX    MySQL

请教一个比较麻烦的 Oracle 转 Mysql 的问题

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  •   darnurash Oct 1, 2022 2877 views
    This topic created in 1320 days ago, the information mentioned may be changed or developed.

    有一个 oracle 的 sql 要转写成 mysql 5.7 的写法,但是有几个分析函数很麻烦:

    SELECT * FROM ( SELECT s.NAME , s.SUBJECT , s.SCORES , s.TERM , ROW_NUMBER() OVER (PARTITION BY SUBJECT ORDER BY SCORES DESC NULLS LAST ) AS rn, count(*) OVER (PARTITION BY SUBJECT ) AS rr, DENSE_RANK() OVER (PARTITION BY SUBJECT ORDER BY SCORES DESC) AS rd FROM SCORES s) FF WHERE FF.rn>2 AND FF.rr>2 AND FF.rd>2

     难点就是实现 ROW_NUMBER() ... NULLS LAST)、count(*) OVER...、DENSE_RANK() OVER 请问有什么快捷的写法么? 
    3 replies    2022-10-01 15:31:47 +08:00
    darnurash
        1
    darnurash  
    OP/div>
       Oct 1, 2022
    建表语句:
    CREATE TABLE "SCORES"
    ( "NAME" VARCHAR2(100),
    "SUBJECT" VARCHAR2(100),
    "SCORES" NUMBER(*,0),
    "TERM" NUMBER(*,0)
    )
    c6h6benzene
        2
    c6h6benzene  
       Oct 1, 2022
    从 Stackoverflow 看到的:

    SELECT
    (@row_number := @row_number + 1) AS rnk, points
    FROM yourTable,
    (SELECT @row_number := 0) AS x
    ORDER BY points DESC;

    至于 DENSE_RANK 大概你得自己写 join 根据 row_number 来判断了(或者丢到前端去)。
    wxf666
        3
    wxf666  
       Oct 1, 2022
    为啥不用 MySQL 8.0 呢?

    这些窗口函数连 SQLite 都已经在 4 年多前支持了。连 SQLite 都不如的,我觉得应该换了
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