请教一下 shell 里使用 jq 处理 json 应该怎么写 - V2EX
Ryanjie
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请教一下 shell 里使用 jq 处理 json 应该怎么写

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  •   Ryanjie Dec 12, 2021 2135 views
    This topic created in 1612 days ago, the information mentioned may be changed or developed.

    如题,有一个 json 文件,

    [ { "id": 0001, "name": "Zhang.San_123456", "email": { "qqmail": "[email protected]", "163mail": "[email protected]" }, "Address": { "Province": "Guangdong", "City": "Zhanjiang", "Country": "Xuwen" } }, { "id": 0002, "name": "Li.Si_123456", "email": { "qqmail": "[email protected]", "163mail": "[email protected]" }, "Address": { "Province": "Sichuan", "City": "Yibin", "Country": "Jiang'an" } }, { "id": 0003, "name": "Wang.Wu_123456", "email": { "qqmail": "[email protected]", "163mail": "[email protected]" }, "Address": { "Province": "Shanxi", "City": "Taiyuan", "Country": "Qingxu" } } ] 

    我想获取里面 name 字段为 Li.Si_123456 的一部分,返回时移除 email 里的 163mail ,返回内容如下:

    [ { "id": 0002, "name": "Li.Si_123456", "url": "http://xxx.com", "qqmail": "[email protected]", "Address": { "Province": "Sichuan", "City": "Yibin", "Country": "Jiang'an" } } ] 

    请教一下这个使用 jq 处理应该怎么写呢,有大佬能指教一下吗?谢谢了^^

    Ryanjie
        2
    Ryanjie  
    OP
       Dec 13, 2021
    @gstqc 谢谢大佬指教
    Ryanjie
        3
    Ryanjie  
    OP
       Dec 13, 2021
    解决方法:
    1. 获取里面 name 字段为 Li.Si_123456 的一部分:`jq --arg NAME ${UserName} '.[] | select(.name==$NAME)'`
    2. 返回时移除 email 里的 163mail: `map({id, name, url, qqmail: .email.qqmail,...})`
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