求一个 go 中的 aes 加密方法

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这是一个创建于 1414 天前的主题，其中的信息可能已经有所发展或是发生改变。

要求如下：

str = `406BF0AD11310101220213481000320000` key := `ER2Fb6ts3ECX` 通过 AES 加密(加解密算法 AES/工作模式 ECB /填充方式 NoPadding)并根据 base64 转码后字符串位: rebZn7aj61hD3lfsUrhwFgVzPg4yYo9aseP/a4sNTRIh/Vtb0mziFfoHdOZBZ5uj

试过了论坛中一位大老的方法,出来的结果貌似不一样呀~

package xaes import ( "bytes" "crypto/aes" "crypto/cipher" "crypto/rand" "crypto/sha256" "encoding/base64" "errors" ) type Aes struct { key []byte } func NewAes(key string) (*Aes) { if key == "" { panic("aes key empty") } sum := sha256.Sum256([]byte(key)) return &Aes{ key:sum[:], } } func (a *Aes) Encrypt(encodeBytes []byte) (val string, err error) { block, err := aes.NewCipher(a.key) if err != nil { return } blockSize := block.BlockSize() encodeBytes = zeroPadding(encodeBytes, blockSize) iv := make([]byte, blockSize) _,err = rand.Read(iv) if err != nil { return } blockMode := cipher.NewCBCEncrypter(block, iv) crypted := make([]byte, len(encodeBytes)) blockMode.CryptBlocks(crypted, encodeBytes) iv = append(iv,crypted...) val = base64.StdEncoding.EncodeToString(iv) return } func (a *Aes) pkCS5Padding(ciphertext []byte, blockSize int) []byte { padding := blockSize - len(ciphertext)%blockSize padtext := bytes.Repeat([]byte{byte(padding)}, padding) return append(ciphertext, padtext...) } func (a *Aes) Decrypt(decodeBytes []byte) (origData []byte,err error) { //decodeBytes, err := base64.StdEncoding.DecodeString(decodeStr) //if err != nil { // return //} block, err := aes.NewCipher(a.key) if err != nil { return nil, err } if len(decodeBytes) < block.BlockSize() { err = errors.New("decodeBytes 长度不足") return } iv := decodeBytes[:block.BlockSize()] decodeBytes = decodeBytes[block.BlockSize():] blockMode := cipher.NewCBCDecrypter(block, iv) origData = make([]byte, len(decodeBytes)) blockMode.CryptBlocks(origData, decodeBytes) origData = zeroUnPadding(origData) return } func (a *Aes) pkCS5UnPadding(origData []byte) []byte { length := len(origData) unpadding := int(origData[length-1]) return origData[:(length - unpadding)] } func zeroPadding(ciphertext []byte, blockSize int) []byte { padding := blockSize - len(ciphertext)%blockSize padText := bytes.Repeat([]byte{0}, padding) return append(ciphertext, padText...) } func zeroUnPadding(origData []byte) []byte { return bytes.TrimFunc(origData, func(r rune) bool { return r == rune(0) }) }

调用方式

package main import ( "awesomeProject/xaes" "fmt" ) func main() { str := []byte("406BF0AD11310101220213481000320000") xa := xaes.NewAes("ER2Fb6ts3ECX") b,e:=xa.Encrypt(str) if e != nil{ fmt.Println(e.Error()) return } fmt.Println(b) }

6 条回复 2021-12-03 12:32:28 +08:00

guader

2021-12-02 17:56:03 +08:00

他这不是 cbc ？

sunmoon1983

2021-12-02 20:57:09 +08:00

@guader 我不知道呀，他给的文档中说的是 ecb....我就没向 cbc 上想呀

buffzty

2021-12-03 01:41:02 +08:00

早上上班就看见你发了,晚上要睡了还没人回你真是醉了
```go
package main

import (
"bytes"
"crypto/aes"
"encoding/base64"
"fmt"
)

func main() {
str := []byte("406BF0AD11310101220213481000320000")
key := make([]byte, 16)
oriKey := []byte("ER2Fb6ts3ECX")
for k, v := range oriKey {
key[k] = v
}
cipher, _ := aes.NewCipher(key)
chunks := arrChunk(str, len(key))
buf := make([]byte, len(key))
encryptData := make([]byte, 0, (len(chunks)+1)*len(key))
for _, chunk := range chunks {
if len(chunk) < len(key) {
chunk = append(chunk, bytes.Repeat([]byte{0}, len(key)-len(chunk))...)
}
cipher.Encrypt(buf, chunk)
encryptData = append(encryptData, buf...)
}
fmt.Println(base64.StdEncoding.EncodeToString(encryptData))
}
func arrChunk(arr []byte, size int) [][]byte {
chunks := make([][]byte, 0)
chunk := make([]byte, 0, size)
for i := 0; i < len(arr); i++ {
chunk = append(chunk, arr[i])
if len(chunk) >= size {
chunks = append(chunks, chunk)
chunk = make([]byte, 0, size)
}
}
chunks = append(chnks, chunk)
return chunks
}
```

buffzty

2021-12-03 01:42:04 +08:00

我真是服这个代码格式化到底咋弄

sunmoon1983

2021-12-03 09:00:57 +08:00

@buffzty 3Q ，能加密出来相要有结果了

Overfill3641

2021-12-03 12:32:28 +08:00

@buffzty 只有主题可以是 Markdown 的....