[ Python ]如何取回生成器的返回值 - V2EX
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[ Python ]如何取回生成器的返回值

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  •   MiketsuSmasher 2021-09-20 23:11:16 +08:00 2546 次点击
    这是一个创建于 1481 天前的主题,其中的信息可能已经有所发展或是发生改变。

    以下是一个校验文件的函数,algorithm_name是哈希类型的名称,checksum是已知的校验码。

    def iter_check(filepath: str | bytes | os.PathLike[str | bytes], algorithm_name: str, checksum: str): algorithm = get_algorithm(algorithm_name) with open(filepath, mode='rb') as file: algorithm_instance = algorithm() for block in iter(partial(file.read, 1024), b''): yield block algorithm_instance.update(block) return algorithm_instance.hexdigest() == checksum 

    其本质上是一个生成器,每一次迭代都会yield一个block。那么,能否取回最后由return返回的校验结果?

    3 条回复    2021-09-25 06:53:40 +08:00
    chenstack
        1
    chenstack  
       2021-09-21 00:58:04 +08:00
    生成器迭代结束后会生成一个 StopIteration,返回值就是这个 StopIteration 的 value
    defiter_check():
    foriinrange(5):
    yieldi
    return10


    checker=iter_check()
    whileTrue:
    try:
    print(next(checker))
    exceptStopIterationase:
    print("result:",e.value)
    break
    BBCCBB
        2
    BBCCBB  
       2021-09-21 09:41:01 +08:00
    for 循环, 或者看一下 next 函数的用法.
    O5oz6z3
        3
    O5oz6z3  
       2021-09-25 06:53:40 +08:00
    基本原理已经被楼上说完了,至于你的需求可以很容易想到一个简单的实现,不知道有没有现成的:
    class wrapiter:
    ... def __init__(self, _iter):
    ... ... self.iter = iter(_iter)
    ... ... self.val = None
    ... def __iter__(self):
    ... ... return self
    ... def __next__(self):
    ... ... try:
    ... ... ... return next(self.iter)
    ... ... except StopIteration as e:
    ... ... ... self.val = e.value
    ... ... ... raise

    it = wrapiter(range(9))
    print([x for x in it])
    print(it.val)
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