V2EX = way to explore V2EX 是一个关于分享和探索的地方
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This topic created in 1772 days ago, the information mentioned may be changed or developed.
dept 结构：
[ { "id": "2", "name": "aaa", "children": [ { "id": "3", "name": "bbb", "children": [ { "id": "4", "name": "ccc", "children": [ ] }, { "id": "5", "name": "ddd", "children": [ ] } ] }, { "id": "6", "name": "eee", "children": [ ] } ] }, { "id": "7", "name": "fff", "children": [ ] } ] user 数据结构：
[ { "id": 2, "name": "aaa", "department": 6 }, { "id": 1, "name": "admin", "department": 7 } ] 合并后的结构：
[ { "id": "2", "name": "aaa", "children": [ { "id": "3", "name": "bbb", "children": [ { "id": "4", "name": "ccc", "children": [ ] }, { "id": "5", "name": "ddd", "children": [ ] } ] }, { "id": "6", "name": "eee", "children": [ ], "users": [ { "id": 2, "name": "aaa" }, ] } ] }, { "id": "7", "name": "fff", "children": [ ], "users": [ { "id": 1, "name": "admin" }, ] } ] 我目前的做法是遍历一遍 dept 列表，找到了一个 dept 就遍历以便 user 列表，如果用户多的话，这样就很慢了…… 有什么更好的办法吗？
 | 1 dayeye2006199 Jun 28, 2021  1 弄个 dept -> user 的 map，是不是就快一些了 |
 | 2 tomkliyes Jun 28, 2021 先遍历一遍 user 得到{dept: users}，再遍历 dept |
 | 3 lanshee Jun 29, 2021 时间空间二选一,想要时间快就 map,空间小就 list. |
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