Java 如何获取聚合查询后 top_hits 中的_source 值？求大佬解答

刚学习 es，这个问题困扰了我很久。。求大佬救救我 查询语句

{ "query": { "term": { "memberid": "2136476" } }, "aggs": { "group": { "terms": { "field": "meetingid", "order": { "addtime": "desc" } }, "aggs": { "result": { "top_hits": { "_source": [ "meetingid", "memo", "addtime" ], "size": 1, "sort": { "addtime": { "order": "desc" } } } }, "addtime": { "max": { "field": "addtime" } } } } } } 

我想要获取_source 的值

最后获取到这一步后卡住了，debug 了一下发现有一个 SearchHit 的值，但我用 getProperty()获取不到，求解答

 SearchResponse respOnse= client.search(request).actionGet(); Aggregations aggregatiOns= response.getAggregations(); Aggregation a = aggregations.get("meeting"); Terms teamSum= (Terms)a; for(Terms.Bucket bucket:teamSum.getBuckets()){ Aggregation aggregation = bucket.getAggregations().get("result"); }