请教 sqlalchemy,如何根据映射类定义去创建表? - V2EX
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qazwsxkevin

请教 sqlalchemy,如何根据映射类定义去创建表?

  •  
  •   qazwsxkevin Jun 13, 2020 1581 views
    This topic created in 2158 days ago, the information mentioned may be changed or developed.

    如:

    Base = declarative_base() engine = create_engine("mysql+pymysql://root:[email protected]:3306/MTData?charset=utf8", echo=False) Session = sessionmaker(bind=engine) session = Session() metadata = MetaData(engine) class tbl_mtLive(Base): __tablename__ = 'mtLive' id = Column(INTEGER(64), primary_key=True) timeline = Column(SMALLINT()) mtuptime = Column(SMALLINT()) mttext = Column(String(500)) mtstatus = Column(String(25)) Strtime = Column(String(25)) fixStrtime = Column(DateTime) mtid = Column(String(10)) UpdateTime = Colum(DateTime) SQLTAG = Column(String(20)) 

    MTData 库里面,除了 mtLive 还有 N 张表,
    有些已经像 class tbl_mtLive(Base)这样“映射类定义”了,
    有些则没有,

    请教大家第一个问题是:如果 mtLive 这个表并没有建立,上面这种 ORM 的前提下,如何以 class tbl_mtLive 去创建表? sqlalchemy 的文档看得眼都花了。。。-_-

    第二个问题是: 想法是打算把库里面的全部表做一个历遍,
    去执行

    for i in #这个表集合如何获取?# session.execute(f"update {i} set `{k}`='{v[0]}' where mtid = '{i.get('mtid')}' AND timeline = '{i.get('timeline')}'") # 更新 UpdateTime session.execute(f"update {i} set `UpdateTime`='{ProcFixTime()}' where mtid = '{i.get('mtid')}' AND timeline = '{i.get('timeline')}'") 

    看了网上的例子,文档和网上有很多的例子是用.cursors,.execute()执行了 SQL 语句,用.fetchall()的方获取到表名,然后开始 do something 的,

    请问 ORM 方式是否有方法可以实现?如何做?

    尽管在草拟这个帖子的前 1 小时,已经实现
    tables = Base.metadata.tables
    print(tables)
    获得了表名,似乎觉得这样操作不是好办法。。。

    2 replies    2020-06-14 23:50:56 +08:00
    gjquoiai
        1
    gjquoiai  
       Jun 14, 2020
    其实没太看懂。。第一个问题应该是 Base.metadata.create_all()?第二个问题可能可以用 automap
    myCupOfTea
        2
    myCupOfTea  
       Jun 14, 2020
    第二个问题直接用 automap 啊
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