用Python做归并排序法出错,求高人指点 - V2EX
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meggy911
V2EX    Python

用Python做归并排序法出错,求高人指点

  •  
  •   meggy911 2013-04-30 15:50:34 +08:00 6475 次点击
    这是一个创建于 4620 天前的主题,其中的信息可能已经有所发展或是发生改变。
    def merge_sort(array,p,q,r):
    n1 = q-p
    n2 = r-q+1
    l = np.zeros(n1+1)
    r = np.zeros(n2+1)
    for i in range(0,n1):
    l[i] = array[p+i]
    for j in range(0,n2):
    r[j] = array[q+j]
    #return r
    l[n1] = float("inf")
    r[n2] = float("inf")
    #return l[0]
    l = sorted(l)
    r = sorted(r)
    #return r
    i = 0
    j = 0
    for k in range(p,r):
    if l[i] <= r[j]:
    array[k] = l[i]
    i = i+1
    else:
    array[k] = r[j]
    j = j+1
    return array
    上面的代码是基于MIT的算法导论一书写的,运行后报错如下:

    >>> merge_sort([4,8,12,1,7,3,9],0,3,6)
    Traceback (most recent call last):
    File "<stdin>", line 1, in <module>
    File "<stdin>", line 16, in merge_sort
    TypeError: range() integer end argument expected, got list.


    请问这是什么原因?代码中加了注释的return r/l用于查错,都没有明显问题,个人怀疑从带k的循环中出现问题,求指导啊求指导!
    7 条回复    1970-01-01 08:00:00 +08:00
    013231
        1
    013231  
       2013-04-30 16:29:00 +08:00
    你不是已出原因了:
    TypeError: range() integer end argument expected, got list.
    Ziya
        2
    Ziya  
       2013-04-30 16:30:17 +08:00   1
    merge_sort的参数r,在def时又定义为一个列表了
    range的参数应该是整数,但是你给它了一个列表
    meggy911
        3
    meggy911  
    OP
      2013-04-30 16:39:15 +08:00
    @Ziya 嗯知道了,本来用l/r表示左右列表的,忘了merge里面还用r定义了数组下标,粗心大意害死人啊
    kaifengjin
        4
    kaifengjin  
       2013-04-30 18:25:29 +08:00   1
    既然是排序算法实现,还用sorted。。。你这只是把原数组分成了两部分,然后用sorted对两部分分别排序,再合并。。。这个分治的过程应该是递归的吧,这样才能体现归并排序啊
    meggy911
        5
    meggy911  
    OP
       2013-04-30 19:58:44 +08:00
    @kaifengjin 嗯确实呀,主要是教材里假设子数组已经排序,自己又刚开始学,所以只会照着教材一步一步来,后面一点就开始介绍递归了
    kaifengjin
        6
    kaifengjin  
       2013-05-01 13:01:03 +08:00
    @meggy911 你可以学习下这里的实现https://github.com/nryoung/algorithms 基本上也是按照算法导论来的。不过建议是先自己根据对书的理解实现,然后再对比看看别人是怎么实现的。
    meggy911
        7
    meggy911  
    OP
       2013-05-02 16:59:24 +08:00
    @kaifengjin 好的,非常感谢!!!
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