基于 bash shell 脚本制定灵活的 trimlog 日志清理策略 - V2EX
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wsgzao
V2EX    程序员

基于 bash shell 脚本制定灵活的 trimlog 日志清理策略

  wsgzao
wsgzao 2019-10-08 17:41:45 +08:00 2389 次点击
这是一个创建于 2261 天前的主题,其中的信息可能已经有所发展或是发生改变。

前言

透过 Zabbix 文件系统监控告警发现日志未定时清理,进一步排查后确认前同事写的 trimlog 脚本在某些服务器上执行定时任务时出现了异常,review 后发现代码逻辑本身没有问题,主要由于 cron job 在执行 date 参数时没有使用转义字符导致,不过 trimlog.sh 这个日志清理脚本代码结构清晰易读,做下共享方便大家参考和二次修改。

基于 bash shell 脚本制定灵活的 trimlog 日志清理策略

更新历史

2019 年 10 月 08 日 - 初稿

阅读原文 - https://wsgzao.github.io/post/trimlog/

扩展阅读

基于 bash find 命令执行 log 日志备份和清理的一次简单实践


问题描述

# 检查 crontab cat /etc/crontab #Ansible: gdp_trim_log 0 1 * * * root /data/release/trimlog.sh '/data/release/log/gop_gdp' 30 1 '*' '%Y%m%d' >> /data/release/trimlog.txt 0 1 * * * root /data/release/trimlog.sh '/data/release/log/cacheupdate' 30 1 '*' '%Y%m%d' >> /data/release/trimlog.txt #Ansible: gdp_trim_backup 0 1 * * * root /data/release/trimbackup.sh '/data/release/backup/gop_gdp' 30 >> /data/release/trimbackup.txt # 检查 crontab 日志 less /var/log/cron Oct 8 01:00:01 sg-gop-10-71-12-146 CROND[183782]: (root) CMD (/data/release/trimlog.sh '/data/release/log/gop_gdp' 30 1 '*' ') Oct 8 01:00:01 sg-gop-10-71-12-146 CROND[183783]: (root) CMD (/data/release/trimbackup.sh '/data/release/backup/gop_gdp' 30 >> /data/release/trimbackup.txt) Oct 8 01:00:01 sg-gop-10-71-12-146 CROND[183784]: (root) CMD (/data/release/trimlog.sh '/data/release/log/cacheupdate' 30 1 '*' ') Oct 8 01:00:01 sg-gop-10-71-12-146 CROND[183786]: (root) CMD (/usr/lib64/sa/sa1 1 1) Oct 8 01:00:01 sg-gop-10-71-12-146 CROND[183788]: (root) CMD (cd /tmp && ss -tna | awk '{print $1}' | sort | uniq -c > snmpss.tmp && chcon system_u:object_r :snmpd_var_run_t:s0 snmpss.tmp && mv -f snmpss.tmp snmpss.cache) Oct 8 01:00:01 sg-gop-10-71-12-146 CROND[183779]: (root) CMDOUT (/bin/bash: -c: line 0: unexpected EOF while looking for matching `'') Oct 8 01:00:01 sg-gop-10-71-12-146 CROND[183779]: (root) CMDOUT (/bin/bash: -c: line 1: syntax error: unexpected end of file) Oct 8 01:00:01 sg-gop-10-71-12-146 CROND[183778]: (root) CMDOUT (/bin/bash: -c: line 0: unexpected EOF while looking for matching `'') Oct 8 01:00:01 sg-gop-10-71-12-146 CROND[183778]: (root) CMDOUT (/bin/bash: -c: line 1: syntax error: unexpected end of file) Oct 8 01:00:01 sg-gop-10-71-12-146 CROND[183777]: (root) CMDOUT (find: ‘/data/release/backup/gop_gdp’: No such file or directory) # 在 crontab 的 date 中加入转移字符即可 0 1 * * * root /data/release/trimlog.sh '/data/release/log/gop_gdp' 30 1 '*' '\%Y\%m\%d' >> /data/release/trimlog.txt 0 1 * * * root /data/release/trimlog.sh '/data/release/log/cacheupdate' 30 1 '*' '\%Y\%m\%d' >> /data/release/trimlog.txt 

bash shell 代码

vim /data/release/trimlog.sh

#!/bin/bash dir=`dirname $0` if [ $# -lt 1 ] then echo "usage: $0 DIRECTORY [DELETE_DAYS] [COMPRESS_DAYS] [COMPRESS_FILE_PATTERN] [DATE_PATTERN]" echo "multiple matches example for COMPRESS_FILE_PATTERN: data|error" exit fi current_date=$(date +"%Y-%m-%d %T") echo "Start trim log at $current_date " path=$1 if [ $# -gt 1 ] then log_delete_days=$2 else log_delete_days=7 fi if [ $# -gt 2 ] then log_compress_days=$3 else log_compress_days=0 fi if [ $# -gt 3 ] then log_compress_match=$4 else log_compress_match='*' fi if [ $# -gt 4 ] then date_pattern=$5 else date_pattern="%Y-%m-%d" fi if [ $log_delete_days -gt 0 ] then files=`ls $path/*.log.*` i=0 while [ $i -le $log_delete_days ] do d=`date "+$date_pattern" --date "$i day ago"` files=`echo "$files"|grep -v $d` i=`expr $i + 1` done echo "$files"|xargs rm -f fi if [ $log_compress_days -gt 0 ] && [ -n "$log_compress_match" ] then files=`ls $path/*.log.*|grep -v "\.gz$"|grep -E "$log_compress_match"` i=0 while [ $i -lt $log_compress_days ] do d=`date "+$date_pattern" --date "$i day ago"` files=`echo "$files"|grep -v $d` i=`expr $i + 1` done echo "$files"|xargs gzip fi current_date=$(date +"%Y-%m-%d %T") echo "Finish trim log at $current_date " 

vim /data/release/trimbackup.sh

#!/bin/bash dir=`dirname $0` if [ $# -lt 1 ] then echo "usage: $0 DIRECTORY [KEEP_BACKUP_NUM]" exit fi current_date=$(date +"%Y-%m-%d %T") echo "Start trim backup at $current_date " path=$1 if [ $# -gt 1 ] then keep_backup_num=$2 else keep_backup_num=10 fi i=0 find $path -maxdepth 1 ! -path $path -type d -printf '%p\n' | sort -r -n | while read dir; do i=`expr $i + 1` if [ $i -gt $keep_backup_num ] then echo "del $dir" rm -rf $dir else echo "keep $dir" fi done current_date=$(date +"%Y-%m-%d %T") echo "Finish trim backup at $current_date " 
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