请教一个数组合并的问题

const arr1 = [
{ id: '150', name: '李三' },
{ id: '151', name: '李三 1' },
{ id: '152', name: '李三 2' },
{ id: '153', name: '李三 3' }
];

const arr2 = [
{ sname: '一级', otor: ['李三 1', '150'] },
{ sname: '一级 2', otor: ['李三 2'] },
{ sname: '一级 3', otor: ['153'] }
];

arr2.map((item, index) => {
const temArr = [];
item.otor.map((ele, idx) => {
const ar = arr1.filter((a, b) => ele === a.id || ele === a.name);
if (ar.length > 0) {
temArr.push(ar[0]);
}
});
item.otor = temArr;
});
console.log(arr2)

@zantop 请教下
假如说再变化一下方式应该是怎么样修改？在第二个数组里面多加了一个新的，在第一个数组里面是没有的。

数组一：[{id:"150",name:"李三"},{id:"151",name:"李三 1"},{id:"152",name:"李三 2"},{id:"153",name:"李三 3"}]

数组二：[{"sname":"一级","otor":["李三 1","150"]},{"sname":"一级 2","otor":["李三 2"]},{"sname":"一级 3","otor":["153"]},{"sname":"一级 4","otor":[{id:"1531",name:"李三 31"}]},]

最后合并成数组：[{"sname":"一级","otor":[{id:"151",name:"李三 1"},{id:"150",name:"李三"}]},{"sname":"一级 2","otor":[{id:"152",name:"李三 2"}]},{"sname":"一级 3","otor":[{id:"153",name:"李三 3"}]},{"sname":"一级 4","otor":[{id:"1531",name:"李三 31"}]

建议把 json 排好版再发，有相关网站。看得难受

@sunriz 好的

arr2.map(v => ({
...v,
otor: [v.otor.map(item => arr1.find(j => (j.id === item || j.name === item)))]
}))

手抖，v.otor 前面多了一对中括号

@source 我看看，受教了