写了一个密码管理的小脚本 - V2EX
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ucun

写了一个密码管理的小脚本

  •  
  •   ucun Mar 6, 2019 3735 views
    This topic created in 2628 days ago, the information mentioned may be changed or developed.

    主要用来管理各登录密码

    只需要记住用户名和用来加密的字符串或者文件。

    可以选复制到剪贴板或者输出到屏幕

     #!/usr/bin/env python3 import os import sys import getpass import hashlib import argparse def md5sum(file): md5_hash = hashlib.md5() try: with open(file, 'rb') as f: for byte in iter(lambda:f.read(65536), b''): md5_hash.update(byte) return md5_hash.hexdigest() except IOError as e: print(e) pass def generate_password(src, user, key, length=12): password = hashlib.sha256((src + user + key).encode()).hexdigest() password = password[0:length] return password class ClipBoard(): @staticmethod def copy(message): platform = sys.platform if 'win32' in platform or 'cyg' in platform: cmd = 'echo {}|clip'.format(message) elif 'linux' in platform: cmd = 'echo {}|xclip'.format(message) os.system(cmd) class GetKey(argparse.Action): def __init__(self, option_strings, dest=None, nargs=0, default=None, required=False, type=None, metavar=None, help=None): super(GetKey, self).__init__(option_strings=option_strings, dest=dest, nargs=nargs, default=default, required=required, type=type, metavar=metavar, help=help) def __call__(self, parser, args, values, option_strings=None): key = getpass.getpass("key or file path:") setattr(args, self.dest, key) def main(): parser = argparse.ArgumentParser(description="generate password") parser.add_argument("src", help="target") parser.add_argument("user", help="username") parser.add_argument("key", action=GetKey, help="the encypt key of file") parser.add_argument("-l", dest='length', type=int, default=12, required=False, help="the length of password") parser.add_argument("-c", dest="copy", action="store_true", default=False, required=False, help="copy to clipboard") args = parser.parse_args() src = args.src user = args.user key = args.key length = args.length copy = args.copy if os.path.isfile(key): key = md5sum(key) password = generate_password(src, user, key, length) if copy: ClipBoard.copy(password) else: print(password) if __name__ == '__main__': main() 

    用法 python3 pypass.py 网站地址 用户名 -l 密码长度 [-c]

    pypass.png

    11 replies    2019-03-07 12:43:29 +08:00
    2exploring
        1
    2exploring  
       Mar 6, 2019
    pass 不好吗。。
    ifaii
        2
    ifaii  
       Mar 6, 2019 via iPhone
    1passwd
    hundan
        3
    hundan  
       Mar 6, 2019 via Android   2
    我不信楼主会用这个来管理自己密码
    CallMeReznov
        4
    CallMeReznov  
       Mar 6, 2019
    我选择 excel。。。。或者 lastpass
    momo1999
        5
    momo1999  
       Mar 6, 2019
    chrome 自带挺好用
    indev
        6
    indev  
       Mar 6, 2019
    再来一次,推荐 lesspass,之前是用 nodejs,最近改为 python 了
    https://github.com/lesspass/lesspass
    masker
        7
    masker  
       Mar 6, 2019 via Android
    chrome 智能填充。chrome 推荐密码。
    harde
        8
    harde  
       Mar 7, 2019
    就目前来说,1password 足够用
    d0m2o08
        9
    d0m2o08  
       Mar 7, 2019
    曾经我也想撸一个自己的,后来用了 keepass+dropbox 组合
    set01
        10
    set01  
       Mar 7, 2019
    lastpass 挺好的,免费版就够用了
    ysc3839
        11
    ysc3839  
       Mar 7, 2019
    我选择 KeePass。
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