不行, 你能正回答出段程序的出? - V2EX
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013231

不行, 你能正回答出段程序的出?

  •   
  •   013231 Sep 13, 2012 3943 views
    This topic created in 4989 days ago, the information mentioned may be changed or developed.
    x = [lambda: x for x in range(10)]
    print x[0]()
    x = (lambda: x for x in range(10))
    print x.next()()
    print [lambda: x for x in range(10)][0]()
  • range
  • print
  • lambda
    5 replies    1970-01-01 08:00:00 +08:00
    likai
        1
    likai  
       Sep 13, 2012
    这和头脑风暴上的一段代码何其相似
    fanzeyi
        2
    fanzeyi  
       Sep 13, 2012
    果不其然的做错了=.=

    答案太丑就不贴了..

    俺来解析下

    https://gist.github.com/3714157

    # 不直接贴出来了 =.=
    pyKun
        3
    pyKun  
       Oct 10, 2012
    x = [lambda: x for x in range(10)]
    这个运行看到结果了，但不明白。。。

    @fanzeyi 看你的解析也没明白。。。
    首先是个list是肯定的，你解析里的的“lambda x”是什么意思？
    013231
        4
    013231  
    OP
       Oct 10, 2012   1
    @pyKun
    x = [lambda: x for x in range(10)]
    x[0]就是lambda: x
    lambda表式中的x引用的是哪量呢? 函作用域内找不到, 就到外作用域即全局作用域去找, 然後找到了.
    也就是x[0]()返回的是x自身.
    pyKun
        5
    pyKun  
       Oct 10, 2012
    @013231 嗯。。明白了。。。
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