Python 实现 - V2EX

Python 实现 - V2EX

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这是一个创建于 2648 天前的主题，其中的信息可能已经有所发展或是发生改变。

0-999 个猴子，每次把奇数个扔出去，剩下的再融合把奇数个扔出去，最后剩下的那个是几号

拜托了

6 条回复 2018-07-30 19:29:40 +08:00

1

blankme

2018-07-27 21:10:22 +08:00

print(math.pow(math.floor(math.log2(n)), 2))

2

wjm2038

2018-07-28 07:25:18 +08:00 via Android

@blankme 999 出结果 81 应该不对吧

3

linbingqinag

2018-07-28 09:05:36 +08:00 via Android

这个你整个递归算下

4

blankme

2018-07-28 09:15:17 +08:00

@wjm2038
我按照 1 - n 写的，思路是一样的

5

blankme

2018-07-28 09:24:49 +08:00

@wjm2038
pow 那个写反了 - -
print(math.pow(2, math.floor(math.log2(n))))

6

wangtianshang

OP

2018-07-30 19:29:40 +08:00 via Android

@blankme 谢谢

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