请教一个 sql 问题 - V2EX
pipixia

请教一个 sql 问题

  •  
  •   pipixia Dec 2, 2017 3465 views
    This topic created in 3083 days ago, the information mentioned may be changed or developed.

    这是搜索结果 这个是符合条件的条目

    当有满足条件的在搜索结果对应 status 加减数值

    这种 sql 怎么写= =

    13 replies    2017-12-03 02:33:03 +08:00
    shiji
        1
    shiji  
       Dec 2, 2017
    表示没读懂题
    x86
        2
    x86  
       Dec 2, 2017
    没理解说什么
    难道说查询统计? COUNT(`status`) AS AS_NAME ?
    340244120
        3
    340244120  
       Dec 2, 2017 via iPhone
    看得我贼特么难受 求大神翻译
    sortbylist
        4
    sortbylist  
       Dec 2, 2017 via Android
    就加减啊,不然就转成 number 加减啊。
    yezhiye
        5
    yezhiye  
       Dec 2, 2017 via Android
    select count(*) -1 where ...
    如果不是我就猜不到你想问什么了。
    187j3x1
        6
    187j3x1  
       Dec 2, 2017
    这描述能力基本告别 sql 开个玩笑
    pipixia
        7
    pipixia  
    OP
       Dec 2, 2017 via Android
    @yezhiye 哇 你 get 到了
    pipixia
        8
    pipixia  
    OP
       Dec 2, 2017 via Android
    @yezhiye 怎么用一条达到效果呢
    pipixia
        9
    pipixia  
    OP
       Dec 2, 2017 via Android
    @187j3x1 见笑了
    yezhiye
        10
    yezhiye  
       Dec 2, 2017 via Android
    @pipixia 基本上就是上条那样了,把约束条件写在 where 后面,例如 where statue = 2。
    c6h6benzene
        11
    c6h6benzene  
       Dec 2, 2017 via iPhone
    如果是要聚合函数结果满足条件的话用 Having,例如 Having Count(*)=1。
    pipixia
        12
    pipixia  
    OP
       Dec 2, 2017 via Android
    @c6h6benzene 感谢明天试一下 目前用的方法是查两条 sql 然后合并计算
    xiangin
        13
    xiangin  
       Dec 3, 2017
    @x86 Oracle 没有 AS 关键字,嘻嘻
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