Python -爬虫-抓取代理 ip 问题

代码发上来看看 没代码怎么分析呢

过滤掉 display:none;

代码如下:

import requests
from lxml import etree

class Proxy(object):
def __init__(self):
self.tm_url = 'http://www.goubanjia.com/free/anoy/%E9%80%8F%E6%98%8E/index{page}.shtml # 1,2,3

def get_proxy(self, url):
r = requests.get(url, headers={
'User-Agent': 'Mozilla/5.0 (Windows x86; rv:19.0) Gecko/20100101 Firefox/19.0,'
})
html = etree.HTML(r.content)
all_proxy = html.xpath('//table//tr[td]')
for i in all_proxy:
ip_port = ''.join(i.xpath('./td[1]/span[@style]/text()|'
'./td[1]/div[@style]/text()|'
'./td[1]/p[@style]/text()|'
'./td[1]/text()|'
'./td[1]/span[@class]/text()'))
ip, port = ip_port.split(':')
anOnymous= i.xpath('./td[2]/a/text()')[0]
http_type = ''.join(i.xpath('./td[3]/a/text()')) or 'http'
proxy = (ip, port, anonymous, http_type)
yield proxy

def start(self):
for page in range(1, 3):
tm_url = self.tm_url.format(page=page)
for proxy in self.get_proxy(tm_url):
yield proxy
if __name__ == '__main__':
p = Proxy()
for i in p.start():
print i

@VicYu ip 可以正确获取，端口有问题

端口肯定利用 js 转换了 我再看看

@xiaobai987 好的

推荐个用着不错的 爬虫代理 ip-chi.net

@niuoh 非常感谢

翻出来了原来写的。。

```python
def goubanjia_com(self, *args):
logger.info('giubanjia.com start')
i = 1
self.THREAD_ID += 1
while(1):
url = 'http://www.goubanjia.com/free/index%d.shtml' % (i)
r = requests.get(url, headers=self.http_headers())
if r.status_code == 404:
break
try:
html = BeautifulSoup(r.text, 'lxml')
tbody = html.tbody
for tr in tbody.find_all('tr'):
p = proxy()

[x.extract() for x in tr.find_all('p')]


try:
_ = tr.find_all('td', {'class':"ip"})[0].text
_ = _.split(':')
p.ip = _[0]
p.port = int(_[1])
# p.port = int(tr.find_all('td', {'data-title':"PORT"})[0].text)

p.safe = tr.find_all('td')[1].text.replace(' ', '').replace('\n', '').replace('\t', '')
p.type = tr.find_all('td')[2].text.replace(' ', '').replace('\n', '').replace('\t', '')
p.place = tr.find_all('td')[3].text.replace(' ', '').replace('\n', '').replace('\t', '').replace('\r', '').replace('\xa0', '')
p.net = tr.find_all('td')[4].text.replace(' ', '').replace('\n', '').replace('\t', '')
except IndexError as e:
print(tr)
logger.error('%s is index error' % p)
# exit(0)

logger.debug('<get>%s' % p)
self.wait_for_verify.put(p)
self.THREAD_ID += 1
self.add_thread(self.verify_proxy_thread, self.THREAD_ID)
logger.debug('%s ok' % url)
gevent.sleep(1)
except AttributeError as e:
print(e)
# print(r.text)
gevent.sleep(10)
logger.error('%s Error, sleep 10s' % url)
continue

# exit()
i += 1

```

晕 这样吧 https://github.com/lc4t/proxypool

var _$ = ['.port', "each", "html", "indexOf", '*', "attr", 'class', "split", " ", "", "length", "push", 'ABCDEFGHIZ', "parseInt", "join", ''];
$(function() {
$(_$[0])[_$[1]](function() {
var a = $(this)[_$[2]]();
if (a[_$[3]](_$[4]) != -0x1) {
return
};
var b = $(this)[_$[5]](_$[6]);
try {
b = (b[_$[7]](_$[8]))[0x1];
var c = b[_$[7]](_$[9]);
var d = c[_$[10]];
var f = [];
for (var g = 0x0; g < d; g++) {
f[_$[11]](_$[12][_$[3]](c[g]))
};
$(this)[_$[2]](window[_$[13]](f[_$[14]](_$[15])) >> 0x3)
} catch (e) {}
})
})
这是解密代码哦

@lc4t
@xiaobai987
非常感谢，我看一看

def get_poxy(port_word):
_, word = port_word.split(' ')
num_list = []
for item in word:
num = 'ABCDEFGHIZ'.find(item)
num_list.append(str(num))

port = int("".join(num_list)) >> 0x3
return port

可以试下我这个函数~ 拿到端口那里的大写字母，传进去就返回了~

@tangzipeng 厉害 关键还是解密 JS

@tangzipeng 很厉害，函数可以获得正确的结果，非常感谢
@xiaobai987 解密代码从哪里可以找到呢？