C++ 传参时候,参数发生改变?! 怎么回事? - V2EX
HxSeek
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C++ 传参时候,参数发生改变?! 怎么回事?

  •  
  •   HxSeek Apr 25, 2015 2177 views
    This topic created in 4038 days ago, the information mentioned may be changed or developed.

    传参数的是,形参和实参不一致了!(调试时候发现的), 本人搞不太懂是什么回事,请各路大神指点一下。。。

    //这是构造函数
    Color::Color(float r, float g, float b, float a)
    {
    R = r;
    G = g;
    B = b;
    A = a;
    }

    //下面三个是操作符重载
    Color Color::operator + (Color &c)
    {
    return Color(R + c.R, G + c.G, B + c.B, A + c.A);
    }

    Color Color::operator - (Color &c)
    {
    return Color(R - c.R, G - c.G, B - c.B, A - c.A);
    }

    //(就是这个操作符重载出了问题上面2个好像都没事)
    Color Color::operator * (float f)
    {
    return (R * f, G * f, B * f, A * f);
    }

    操作语句:
    float x;

    float y;
    float slope;

    float xdiff = x2 - x1;
    float ydiff = y2 - y1;

    slope = ydiff / xdiff;
    for(x=x1; x<=xdiff; x+=1.0f)
    {

    y = ((x - x1) * slope) + y1;
    Color color = color1 + ((color2 - color1) * ((x - x1) / xdiff));(主要是这句)
    }

    我感觉我操作符重载没写错但是构造的时候就错了如果不是操作符重载的问题,又会是什么问题呢?

    6 replies    2015-04-26 01:19:48 +08:00
    ljcarsenal
        1
    ljcarsenal  
       Apr 25, 2015   1
    return (R * f, G * f, B * f, A * f); ??

    不应该是 return Color(R * f, G * f, B * f, A * f); ?
    HxSeek
        2
    HxSeek  
    OP
       Apr 25, 2015
    对哦,原理是我粗心```
    opkgopkg
        3
    opkgopkg  
       Apr 25, 2015 via Android
    萌萌。
    lirau
        4
    lirau  
       Apr 25, 2015
    eastphoton
        5
    eastphoton  
       Apr 25, 2015
    呵呵
    VirgilMing
        6
    VirgilMing  
       Apr 26, 2015 via iPhone
    为啥那个错的重载可以编译通过?float 可以隐式转换为自定义类?
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