已知ABC为三角, 边AB 长度为 w, AB和AC长度相等, BC长度为 n, A坐标(xA, yA), B坐标(xB, yB); 求C坐标(xC, yC)
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 | 1 GordianZ Aug 19, 2010 画个图用勾股定理都能算出来，就这么点动手能力都没有？ http://en.wikipedia.org/wiki/Triangulation |
 | 2 badec Aug 19, 2010 呃，确实也有数学不好的人. |
 | 3 utom OP (xa-xb)+(ya-yb)=w (xa-xc)+(ya-yc)=w (xb-xc)+(yb-yc)=n 求xc yc |
 | 6 explon Aug 19, 2010 无聊人士 |
 | 7 jiangxiaolei Aug 19, 2010 炫耀贴~ |
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