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关于 Shuffle 实现代码的三点疑惑

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  •   vexfisher 2014-08-25 14:56:22 +08:00 3910 次点击
    这是一个创建于 4148 天前的主题,其中的信息可能已经有所发展或是发生改变。
    python的shuffle代码是通过随机交换两个下标的值来达到洗牌的目的。
    疑惑1:为什么要用倒序循环?
    疑惑2:xrange中为什么不是从0开始?
    疑惑3:在语句`j= _int(random() * (i+1))`中,j可以取到的最大值是i,这样岂不是达不到交换值的目的了?我的理解是`j= _int(random() * i)` ,这样保证 0<j<i 。


    def shuffle(self, x, random=None):

    if random is None:
    random = self.random
    _int = int
    for i in reversed(xrange(1, len(x))):
    # pick an element in x[:i+1] with which to exchange x[i]
    j = _int(random() * (i+1))
    x[i], x[j] = x[j], x[i]

    python新手先谢过大家了。
    4 条回复    2014-08-25 21:39:10 +08:00
    hahastudio
        1
    hahastudio  
       2014-08-25 15:17:55 +08:00   1
    vexfisher
        2
    vexfisher  
    OP
       2014-08-25 21:19:12 +08:00
    "If the random number generator can return a random integer p ≤ j < q for specified parameters p, q"


    @hahastudio 谢过haha君
    eriale
        3
    eriale  
       2014-08-25 21:38:22 +08:00   1
    具体研究过,不过洗牌程序的随机性你可以通过代码来测试,就是对一个队列反复洗牌,并统计出现的位置。
    已经有人讨论过怎么测试洗牌程序了:
    http://coolshell.cn/articles/8593.html

    https://gist.github.com/GTxx/2796868275375f6bd877
    eriale
        4
    eriale  
       2014-08-25 21:39:10 +08:00
    @eriale 具体没研究过。。。。少打一个字
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