奇怪的小问题 - V2EX
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roker
V2EX    Lua

奇怪的小问题

  •   
  •   roker May 4, 2024 3718 views
    This topic created in 739 days ago, the information mentioned may be changed or developed.
    local inputString = '[[123],[456],[789]]'
    local st=(string.find(inputString,"]",-1))
    上面能正常匹配。
    local end=(string.find(inputString,"[",-1))
    然后就报错 string = '[string "..."]:17: malformed pattern (missing ']')'
    google 说需要把"["把[转义成正则表达式的[加%
    local end=(string.find(inputString,"%[",-1))
    然后 end 的值为 nil ，依然没有获取到，这个是怎么回事
  • string
  • find
  • pattern
    2 replies
    body007
        1
    body007  
       May 4, 2024
    看起来是 lua 语言。根据下面的描述。

    string.find(目标字符串, 搜索字符串, [(init: 起始位置,默认为 1,可为负数表示从后往前), [(plain: false=简单模式,true=正则匹配,默认 false)]])

    你第 3 个参数是 -1 ,那么表示从最后一个字符往后匹配，当然能匹配 ']' 无法匹配 '[' 了

    试试：local st=(string.find(inputString,"%[",-6))，刚好匹配倒数第 1 个 '['
    wellerman
        2
    wellerman  
       May 4, 2024
    local end=(string.find(inputString,"%[",1))
    查找索引开始位置：设为 1 就行了。

    https://www.lua.org/manual/5.3/manual.html#pdf-string.find
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