V2EX takemyhate
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takemyhate

takemyhate

V2EX 第 629012 号会员,加入于 2023-05-15 14:26:19 +08:00
takemyhate 最近回复了
2023-05-22 10:07:59 +08:00
回复了 jacky0983 创建的主题 上海 华为云返现 20%,有人感兴趣嘛?
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function findPath(data, target) {
let path = ""; // 用于存储路径

function traverse(node, currentPath) {
if (node.name === target) {
path = currentPath; // 找到目标节点时更新路径
return;
}

if (node.childs) {
for (let i = 0; i < node.childs.length; i++) {
const child = node.childs[i];
const newPath = currentPath ? `${currentPath} / ${child.name}` : child.name;
traverse(child, newPath); // 递归遍历子节点
}
}
}

traverse(data, "");

return path;
}

// 测试
var data = [
{
name: "手机",
childs: [
{
name: "iPhone",
childs: [
{ name: "iPhone X" },
{ name: "iPhone XR" },
{ name: "iPhone XS" },
],
},
{
name: "HUAWEI",
childs: [
{ name: "HUAWEI Mate 20" },
{ name: "HUAWEI Mate 20 X" },
{ name: "HUAWEI Mate 20 Pro" },
],
},
],
},
];

console.log(findPath(data[0], "HUAWEI Mate 20")); // 输出 "手机 / HUAWEI / HUAWEI Mate 20"
//findPath 函数接受两个参数:data 是树的根节点,target 是要查找的目标节点的名称。函数通过递归遍历树的节点,每次遍历时更新当前路径,并检查当前节点是否为目标节点,如果是则将路径存储到 path 变量中。最终返回得到的路径。这个可以适用于多层的数据结构,因为它通过递归方式遍历树的每个节点,不论树的深度有多大,都能正确地找到路径。
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